13x^2+142x-11=0

Solution for 13x^2+142x-11=0 equation:

13x^2+142x-11=0

a = 13; b = 142; c = -11;
Δ = b2-4ac
Δ = 1422-4·13·(-11)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(142)-144}{2*13}=\frac{-286}{26}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(142)+144}{2*13}=\frac{2}{26}
=1/13
$